Java example - the intersection of arrays
The following example demonstrates how to use retainAll () method to calculate the intersection of two arrays:
/* author by w3big.com 文件名:Main.java */ import java.util.ArrayList; public class Main { public static void main(String[] args) { ArrayList objArray = new ArrayList(); ArrayList objArray2 = new ArrayList(); objArray2.add(0,"common1"); objArray2.add(1,"common2"); objArray2.add(2,"notcommon"); objArray2.add(3,"notcommon1"); objArray.add(0,"common1"); objArray.add(1,"common2"); objArray.add(2,"notcommon2"); System.out.println("array1 数组元素:"+objArray); System.out.println("array2 数组元素:"+objArray2); objArray.retainAll(objArray2); System.out.println("array2 & array1 数组交集为:"+objArray); } }
The above code is run output is:
array1 数组元素:[common1, common2, notcommon2] array2 数组元素:[common1, common2, notcommon, notcommon1] array2 & array1 数组交集为:[common1, common2]